C：转换到华氏摄氏度 [英] C: converting Farenheit to Celsius

问题描述

int main (void)
{
    int fahrenheit; // fahrenheit stands for fahrenheit
    double c; // c stands for celsius

    printf("Enter your fahrenheit, we'll covnvert it into celsius! ");
    scanf("%f", &fahrenheit);

    c = 5/9 * (fahrenheit - 32);
    printf("Here is your %f in celsius!.\n");

    return (0);
}

我跟着突破点code，当它发生在我的输入计算关闭，但公式是正确的。某种逻辑错误，我不能把我的手指上。请帮助！

I've followed the code through break points and when it takes in my input the calculations are off, but the formula is correct. Some sort of logic error I can't put my finger on. Please help!

推荐答案

的 scanf函数呼叫使用了错误的格式字符串。您正在阅读的 INT ，所以你需要它是：

The scanf call uses the wrong format string. You are reading an int so you need it to be:

scanf("%d", &fahrenheit);

---

这位前pression 5/9 用整数除法计算。事实上，编译器在编译的时候做出来。这当然pression计算结果为 0 。

---

The expression 5/9 is evaluated using integer division. In fact the compiler can work it out at compile time. That expression evaluates to 0.

您需要执行浮点除法。例如：

You need to perform floating point division. For instance:

5.0/9

或者

5/9.0

或者

5.0/9.0

您只需要至少一个操作数是浮点值。

You just need at least one operand to be a floating point value.

把这个放入你的前pression，你可以写：

Putting this into your expression, you can write:

c = 5.0/9.0 * (fahrenheit - 32);

和得到您所期望的答案。

and obtain the answer that you expect.

您的printf 说法是错误的了。您应该启用警告，并让编译器告诉你。你的意思写的：

Your printf statement is wrong too. You should enable warnings and let the compiler tell you that. You meant to write:

printf("Here is your %f in celsius!.\n", c);

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