Powershell 新计划任务设置集 [英] Powershell New-ScheduledTaskSettingsSet

问题描述

我尝试添加

但实际的 powershell 只允许我选择 Parallel、Queue 或 IgnoreNew.

为什么我不能使用 StopExisting?

解决方案

如果你看看 MultipleInstances 属性是如何定义的，你会发现它的类型是 not 实际上 TaskMultipleInstancePolicy，但生成的类型名为 MultipleInstancesEnum:

PS C:\>(New-ScheduledTaskSettingsSet |Get-Member MultipleInstances).DefinitionSystem.Object MultipleInstances {get=[Microsoft.PowerShell.Cmdletization.GeneratedTypes.ScheduledTask.MultipleInstancesEnum]($this.PSBase.CimInstanceProperties['MultipleInstances'].Value);set=$this.PSBase.CimInstanceProperties['MultipleInstances'].值 = [Microsoft.PowerShell.Cmdletization.GeneratedTypes.ScheduledTask.MultipleInstancesEnum]($args[0]);}

这已作为Microsoft Connect 上的错误，如果您想更改它，请对其进行投票.

报告者还建议了一种解决方法，将值设置为 StopExisting:

$StopExisting = New-ScheduledTaskSettingsSet$StopExisting.CimInstanceProperties['MultipleInstances'].Value=3

I try to add New-ScheduledTaskSettingsSet with custom settings. As per Technet, there is possible options for MultipleInstances and including StopExisting value.

But actual powershell allows me choose only Parallel, Queue or IgnoreNew.

Why I can't use StopExisting?

解决方案

If you take a look how the MultipleInstances property is defined, you'll see that it's type is not actually TaskMultipleInstancePolicy, but a generated type named MultipleInstancesEnum:

PS C:\>(New-ScheduledTaskSettingsSet |Get-Member MultipleInstances).Definition
System.Object MultipleInstances {get=[Microsoft.PowerShell.Cmdletization.GeneratedTypes.ScheduledTask.MultipleInstancesEnum]($this.PSBase.CimInstanceProperties['MultipleInstances'].Value);set=$this.PSBase.CimInstanceProperties['MultipleInstances'].Value = [Microsoft.PowerShell.Cmdletization.GeneratedTypes.ScheduledTask.MultipleInstancesEnum]($args[0]);}

This has been filed as a bug on Microsoft Connect, upvote it if you want it changed.

The reporter also suggests a workaround to set the value to StopExisting:

$StopExisting = New-ScheduledTaskSettingsSet
$StopExisting.CimInstanceProperties['MultipleInstances'].Value=3

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