使用COUT打印的字符数组的全部内容 [英] Using cout to print the entire contents of a character array

问题描述

我很新的C ++（只是在Java中一个摇摇欲坠的背景）和我难倒关于如何打印出一个字符数组的全部内容。我相信我需要使用一个循环，并立足于数组的长度循环，但我尝试编译未成功的会议。这是我现在所拥有的。预先感谢您的帮助！

 的#include＆LT;＆iostream的GT;
＃包括LT＆;串GT;使用命名空间std;无效namePrinting（字符名称[]）
{
   INT I = 0;
   COUT＆LT;＆LT; 名称： ;
   而（ⅰ＆下; = name.length（））
   {
   COUT＆LT;＆LT;名称[我]
   我++;
   }}诠释的main（）
{
   字符串全名;
   COUT＆LT;＆LT; 输入名字： ;
   CIN＆GT;＆GT;全名;
   焦炭nameArray [fullName.length（）];
   namePrinting（nameArray）;
}
 

解决方案

先从简单的东西：

 字符c_array [3];
c_array [0] ='A';
c_array [1] ='B';
c_array [2] ='c'的;对（INT I = 0;我3; ++ⅰ）
{
  COUT＆LT;＆LT; c_array [I];
}
COUT＆LT;＆LT; ENDL;
 

，直到你明白那么多完美，不要走的更远。现在请注意，如果你空终止该数组，您可以通过整个事情 COUT 和运营商的LT;＆LT; 会知道何时停止：

 字符c_array [4];
c_array [0] ='A';
c_array [1] ='B';
c_array [2] ='c'的;
c_array [3] = 0;COUT＆LT;＆LT; c_array＆LT;＆LT; ENDL;
 

的你不能做到这一点与大多数其他类型的数组。的现在发现，你可以在的char [] 这种方式分配，它会是空终止的：

 字符c_array [20] =ABC;
COUT＆LT;＆LT; c_array＆LT;＆LT; ENDL;
 

您甚至可以省略数组的大小，编译器会推断出它：

 字符c_array [] =ABC; //这是一个char [4];
COUT＆LT;＆LT; c_array＆LT;＆LT; ENDL;
 

有几个不同的方法来读取用户输入到一个数组，但它听起来好像你已经知道了，而这个答案越来越长。

I am quite new to C++ (just a shaky background in Java) and I'm stumped about how to print out the entire contents of a char array. I believe I need to use a loop, and base the loop on the length of the array, but my attempts to compile aren't meeting with success. This is what I have right now. Thanks in advance for your help!

#include <iostream>
#include <string>

using namespace std;

void namePrinting(char name[])
{
   int i = 0;
   cout << "Name: ";
   while(i <= name.length() )
   {
   cout << name[i];
   i++;
   }

}

int main()
{
   string fullName;
   cout << "Enter name: ";
   cin >> fullName;
   char nameArray[fullName.length()];
   namePrinting(nameArray);
}

解决方案

Start with something simple:

char c_array[3];
c_array[0] = 'a';
c_array[1] = 'b';
c_array[2] = 'c';

for(int i=0 ; i<3 ; ++i)
{
  cout << c_array[i];
}
cout << endl;

Do not go farther until you understand that much perfectly. Now notice that if you null-terminate the array, you can pass the whole thing to cout, and operator<< will know when to stop:

char c_array[4];
c_array[0] = 'a';
c_array[1] = 'b';
c_array[2] = 'c';
c_array[3] = 0;

cout << c_array << endl;

You cannot do that with arrays of most other types. Now notice that you can assign a char[] this way, and it will be null-terminated:

char c_array[20] = "abc";
cout << c_array << endl;

You can even omit the size of the array, and the compiler will infer it:

char c_array[] = "abc";    // this is a char[4];
cout << c_array << endl;

There are a couple of different ways to read user input into an array, but it sounds as if you know that already, and this answer is getting long.

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