检测、更改或删除现有的变异观察者 [英] Detect, change or remove existing mutation observer

问题描述

如果某个 JS 添加了一个变异观察者，其他 JS 是否有可能检测、删除、替换或更改该观察者?我担心的是，如果某些 JS 旨在破坏某些 DOM 元素而不被发现，那么 JS 可能想要摆脱任何观察该 DOM 元素的观察者.

If a mutation observer is added by some JS is it possible for other JS to detect, remove, replace or change that observer? My concern is that if some JS aims to corrupt some DOM element without being discovered that JS may want to get rid of any observers watching that DOM element.

推荐答案

我不确定检测是否已经安装了观察者，但是可以通过使用空函数重新观察感兴趣的节点来有效地删除它们.如果存在，重新观察节点将替换之前的观察者函数.

I'm not sure about detecting whether an observer is already installed, but they can be effectively deleted by re-observing the nodes of interest using an empty function. Re-observing a node will replace the previous observer function if one was present.

var observerRef = window.MutationObserver || window.WebKitMutationObserver || window.MozMutationObserver;

// Empty function here to replace whatever might have been installed on targets
var observer = new observerRef( function (mutations) { } );

// Could also be id=someid, etc
var targets = document.querySelectorAll('[class=someclassname]'); 

// Update/replace the observers on all the targets
for(var i = 0; i < targets.length; ++i) {
    observer.observe(targets[i], { attributes: true, childList: true, characterData: false } );
}

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