sed 使用以下命令替换以特定模式开头的行中的单词 [英] sed replace a word at a line which begins with a specific pattern using

问题描述

如何在 FreeBSD 上替换以特定模式开头的行中的单词?考虑以下文件内容:

How can I replace a word at a line which begins with a specific pattern on FreeBSD? Consider the following file contents:

this is to test 
that was for test

我想替换测试"在以this"开头的行.

I want to replace "test" at the line which begins with "this".

推荐答案

为了对以 this 开头的行执行替换，请说:

In order to perform a replacement for lines starting with this, say:

$ sed '/^this/ s/test/something/' inputfile
this is to something 
that was for test

这将在以 this 开头的行上用 something 替换单词 test.

This would replace the word test with something on lines starting with this.

如果要替换匹配行上的所有 test 实例，请为 sed 提供 g 选项:

If you want to replace all instances of test on the matching lines, supply the g option to sed:

sed '/^this/ s/test/something/g' inputfile

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