你如何排序结构的迅速数组 [英] How do you sort an array of structs in swift

问题描述

我有一个结构的数组，我希望能够通过任何两个变量的使用排序（）进行排序，如果可能的

I have an array of a struct and I would like to be able to sort it by either of the two variables using sort() if possible

struct{
    var deadline = 0
    var priority = 0
}

我的斯威夫特编程语言的文档中看着排序（），但只显示简单的数组。可以排序（）一起使用，否则我将不得不建立自己的？

I looked at sort() in the documentation for the Swift programming language but it shows only simple arrays. can sort() be used or will I have to build my own?

推荐答案

排序功能娄是完全一样的，唯一的区别是如何短期和前pressive它们分别是：

Sort within the same array variable

Sort functions bellow are exactly the same, the only difference how short and expressive they are:

完整声明：

myArr.sort { (lhs: EntryStruct, rhs: EntryStruct) -> Bool in
    // you can have additional code here
    return lhs.deadline < rhs.deadline
}

缩短封闭声明：

myArr.sort { (lhs:EntryStruct, rhs:EntryStruct) in
    return lhs.deadline < rhs.deadline
}
// ... or even:
myArr.sort { (lhs, rhs) in return lhs.deadline < rhs.deadline }

紧凑型封声明：

myArr.sort { $0.deadline < $1.deadline }

排序到一个新的数组变量

完整声明：

let newArr = myArr.sorted { (lhs: EntryStruct, rhs: EntryStruct) -> Bool in
    // you can have additional code here
    return lhs.deadline < rhs.deadline
}

缩短封闭声明：

let newArr = myArr.sorted { (lhs:EntryStruct, rhs:EntryStruct) in
    return lhs.deadline < rhs.deadline
}
// ... or even:
let newArr = myArr.sorted { (lhs, rhs) in return lhs.deadline < rhs.deadline }

紧凑型封声明：

let newArr = myArr.sorted { $0.deadline < $1.deadline }

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