如何确定C中的数组elemnts多少？ [英] How to determine the number of array elemnts in C?

问题描述

我在C（我用gcc 4.8.0）的函数接收一个数组作为它的参数。有没有办法准确地确定数组中元素的个数，不传递一个额外的参数array_count？

I have a function in C (I am using gcc 4.8.0) which receives an array as its argument. Is there a way to accurately determine the number of elements in the array, without passing an additional argument array_count?

推荐答案

阵列衰变到函数参数指针所以无法确定大小。

Arrays decay into pointers in function arguments so size cannot be determined.

这是左值[见问题2.5 ]型数组的-T出现在一个前pression衰变（有三个例外）到一个指向它的第一要素;所得指针的类型是指针到-T，因为阵列是不是一个修改的左值，

An lvalue [see question 2.5] of type array-of-T which appears in an expression decays (with three exceptions) into a pointer to its first element; the type of the resultant pointer is pointer-to-T because an array is not a "modifiable lvalue,"

（例外情况是，当阵列是sizeof的或放大器的操作数;操作者，或为字符阵列的文字串初始化）

(The exceptions are when the array is the operand of a sizeof or & operator, or is a literal string initializer for a character array.)

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