find -exec 上的多个 sed 操作 [英] Multiple sed operations on find -exec

问题描述

我正在尝试对 find -exec 操作执行多个 sed 操作.我的代码如下所示:

I am trying to execute multiple sed operations on the find -exec operation. My code looks like this:

find . -name '*.html.haml' -exec sed -i '' 's/restaurant_id/company_id/g' && sed -i '' 's/restaurants/companies/g' && sed -i '' 's/restaurant/company/g' && sed -i '' 's/Restaurants/Companies/g' && sed -i '' 's/Restaurant/Company/g' "{}" \;

这似乎不起作用.我怎么能这样做?

This seems not to work. How could I do that?

错误:

find: -exec: no terminating ";" or "+"

推荐答案

正如其他人所说，问题在于 && 被解释为执行 sed 命令 find 命令完成，而不是传递一串要在每个文件上执行的命令.

As others have said, the problem is that the && is interpereted to execute the sed command after the find command is finished, instead of passing one string of commands to be executed on each file.

获得所需结果的最简单方法是将所有这些组合成一个带有分号的 sed 命令.像这样:

The easiest way to achieve your desired result is to combine this all into one sed command with semicolons. Like so:

$ find . -name '*.html.haml' -exec sed -i 's/restaurant_id/company_id/g;s/restaurants/companies/g;s/restaurant/company/g;s/Restaurants/Companies/g;s/Restaurant/Company/g' "{}" \;

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