find -exec cmd {} + vs | xargs [英] find -exec cmd {} + vs | xargs

问题描述

哪一个比一组非常大的文件更有效，应该使用？

  find。 -exec cmd {} + 
  

或

  find。 | xargs cmd 
  

（假设文件名中没有有趣的字符）

$ b $

但是你必须确保：

>

1. 您的脚本不会假设
   文件在
   文件名中没有空格，




2. 您的脚本不会处理以开头的文件 -




因此，您的代码应如下所示：

 查找。 -exec cmd -option1 -option2  -  {} + 
  

或

 查找。 -print0 | xargs -0 cmd -option1 -option2  -  
  

第一个版本更短，可以忽略1，但是
第二个版本更加可移植和安全，因为 -exec cmd {} + 是一个相对较新的选项在GNU findutils 2005，很多运行系统将没有它），最近是越野车。也有很多人不知道这个 -exec cmd {} + ，你可以从其他答案看到。

Which one is more efficient over a very large set of files and should be used?

find . -exec cmd {} +

or

find . | xargs cmd

(Assume that there are no funny characters in the filenames)

解决方案

Speed difference will be insignificant.

But you have to make sure that:

1. Your script will not assume that no file will have no space, tab, etc in file name; the first version is safe, the second is not.

2. Your script will not treat a file starting with "-" as an option.

So your code should look like this:

find . -exec cmd -option1 -option2 -- {} +

or

find . -print0 | xargs -0 cmd -option1 -option2 --

The first version is shorter and easier to write as you can ignore 1, but the second version is more portable and safe, as "-exec cmd {} +" is a relatively new option in GNU findutils (since 2005, lots of running systems will not have it yet) and it was buggy recently. Also lots of people do not know this "-exec cmd {} +", as you can see from other answers.

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