Python中的平方数列 [英] Square number sequence in Python

问题描述

我是 python 新手，我正在尝试编写代码来打印所有平方数，直到用户输入的所需值的平方为止.

I'm new to python and I am trying to make a code to print all the square numbers until the square of the desired value entered by the user.

    n = raw_input("Enter number")

    a = 1

    while a < n:
            a = 1
            print(a*a)
            a += 1
            if a > n:
            break

当我运行此代码时，它会无限打印1"；...我猜 a 的值不会增加 += 所以它永远是 a=1 .我该如何解决这个问题?

When I run this code it infinitely prints "1" ... I'm guessing that the value of a does not increase by += so it's a=1 forever. How do I fix this?

推荐答案

存在一些问题.首先，您的输入(raw_input() 返回的内容)是一个字符串，因此您必须将其转换为整数:

There are some problems. First, your input (what raw_input() returns) is a string, so you must convert it to integer:

n = int(raw_input(...))

其次，您在每次迭代中都设置 a = 1，因此，由于循环条件是 a <n，循环将永远运行(如果 n > 1).您应该删除该行

Second, you are setting a = 1 each iteration, so, since the loop condition is a < n, the loop will run forever ( if n > 1). You should delete the line

a = 1

最后，没有必要检查 a >n，因为循环条件会处理它:

Finally, it's not necesary to check if a > n, because the loop condition will handle it:

while a < n:
    print a * a
    a += 1

    # 'if' is not necessary

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