反序列化多个 JSON 变量时遇到问题 [英] Having trouble deserializing multiple JSON variable

问题描述

我编写了以下代码，它确实反序列化并解析了单个 JSON 变量，但是，它不适用于多个

I wrote the following code, it does deserialize and parse a single JSON variable, however, it won't work with multiple

API 检索到的 JSON 有类似下面的变量，但是，第一个分支有一个总是变化的数字，比如 value_abc_######，其中 ###### 是一个总是不同的数字，所以我不知道我得到了什么输出.

The JSON retrieved by API has variables similar to the following, however, the first branch has a number that always changes, like value_abc_######, where ###### is a always different number, so I have no idea on what output I get for this one.

这是我通过 API 调用返回的 JSON 结构:

This is the JSON structure I get returned by the API call:

{
  "value_abc_154649": {
    "Name": "",
    "Address": "",
    "Phone": "",
  },
  "value_abc_616447": {
    "Name": "",
    "Address": "",
    "Phone": "",
  },
  "value_abc_912374": {
    "Name": "",
    "Address": "",
    "Phone": ""
  }
}

虽然这是我写的代码，但如果 JSON 只有 1 个分支结果，它可以正常工作，但如果有多个则不会

While this is the code I wrote, it works fine if the JSON has only 1 branch result, but with multiples it won't

    class getVariables
    {   
        public string Name { get; set; }
    }

    class fetch
    {
        var client = new System.Net.WebClient();
        string json = client.DownloadString(API_URL);
        var result = JsonConvert.DeserializeObject<getVariables>(json);
        Console.Write("\nName: " + result.Name); //this just print an empty value

        /*I also tried this structure but the for loop doesn't work
        for (result)
        {
            Console.Write("\nName: " + result.Name);
        }*/
    }

推荐答案

你的类不代表你的 json 结构.尝试反序列化为 Dictionary:

You class does not represent your json structure. Try deserializing to Dictionary<string, getVariables>:

        var json = @"{
        ""value_abc_154649"": {
            ""Name"": """",
    ""Address"": """",
    ""Phone"": """",
  },
  ""value_abc_616447"": {
            ""Name"": """",
    ""Address"": """",
    ""Phone"": """",
  },
  ""value_abc_912374"": {
            ""Name"": """",
    ""Address"": """",
    ""Phone"": """"
  }
    }";

    var result = JsonConvert.DeserializeObject<Dictionary<string, getVariables>>(json);
    // foreach(var r in result.Values)
    // {
    //    Console.Write("\nName: " + r.Name);
    //}
    // or to print with keys: 
    foreach(var kvp in result)
    {
        Console.WriteLine($"Key: {kvp.Key}, Name: {kvp.Value.Name}");
    }

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