字典更新序列元素错误 [英] dictionary update sequence element error

问题描述

我有好几个字典文件，我想用这段代码打开每个文件并把它加到一个集合中，以便以后比较和匹配.基本上我有所有可能字符的所有排列的不同列表，我需要知道排列是否在字典中.但是，当我尝试使用所有字典行进行设置时，出现此错误:

choices = ['s','m','o','k','e','j','a','c','k']def解析(选择):我的集合 = {}对于选择项:文件名 = self.location + "/dicts/%s.txt" % (item)mySet.update(open(filename).read().splitlines())返回我的集合

我收到此错误

错误:字典更新序列元素#0 的长度为4；2 是必需的

另外，我想问一下，是否有可能在不到 1 分钟的时间内运行的两组数据(9 个字符排列和 9 个字典文件列表)之间的比较方法.

我知道已经有关于这个错误的问题，但坦率地说，我是一个初学者，我不明白这些问题与我的代码有什么关系，或者如何修复它.

解决方案

如果你写:

mySet = {}

mySet 是不是set，而是字典(是的，这很令人困惑).例如:

<预><代码>>>>类型({})<类'dict'>

为了构造一个空集，你应该使用:

mySet = set()

set 确实有一个函数 update ，它将所有添加到集合中的可迭代元素作为输入.另一方面，字典需要可迭代的元组(或字典等)

I have several dictionary files, I want this code to open each file and add it to a set, for later comparison and matching. Basically I have a different list of all permutations of all possible characters and I need to know if permutation is in dictionary. But when I try to make a set with all dictionary lines I get this error:

choices = ['s','m','o','k','e','j','a','c','k']
def parsed(choices): 
    mySet = {}

    for item in choices: 
        filename = self.location + "/dicts/%s.txt" % (item)
            mySet.update(open(filename).read().splitlines())

    return mySet  

I get this error

error: dictionary update sequence element #0 has length 4; 2 is required

Furthermore, I'd like to ask if there's a possible comparison method between two sets of data (9 character permutations, and 9 dictionary files list) that runs in less than 1 minute.

I understand that there are already questions regarding this error, but frankly I'm a beginner and I don't understand how those relate to my code, or how to fix it.

解决方案

If you write:

mySet = {}

mySet is not a set, but a dictionary (yeah that is confusing). For instance:

>>> type({})
<class 'dict'>

In order to construct an empty set, you should use:

mySet = set()

A set indeed has a function update that takes as input an iterable of elements that are all added to the set. A dictionary on the other hand requires an iterable of tuples (or a dictionary, etc.)

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