我需要一个Javascript文字语法转换器/反混淆工具 [英] I need a Javascript literal syntax converter/deobfuscation tools
问题描述
我已搜查谷歌的转换器，但我没有发现任何东西。是否有任何可用的工具或我必须做一个脱code我模糊JavaScript code？
我presume有这样的工具，但我不会用正确的关键字搜索谷歌。
在code为3页长，这就是为什么我需要一个工具。
下面是code的为例：
<$p$p><$c$c><script>([][(![]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+!+[]]+(!![]+[])[+[]]][([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[+!+[]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]()[(!![]+[])[!+[]+!+[]+!+[]]+(+(+[])+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[!+[]+!+[]+!+[]+[+[]]]+(![]+[])[+!+[]]+(![]+[])[!+[]+!+[]]])(([]+[])[([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+感谢您
这问题已经被接受的答案，但我仍然会后明确一些事情了。
当这个想法出现的时候，一些人提出了发电机来恩$ C $çJavaScript的这种方式。正是基于这样 [] [排序] [呼]（）[的eval]（/ * code这里* /大BLOB）。因此，您可以通过删除排序呼叫的eval部分（即第一个1628字节）取消code此连接$ C $的结果CR容易。在这种情况下，它产生
如果（的document.cookie ==6ffe613e2919f074e477a0a80f95d6a1）{警报（布拉沃）; }
其他{document.location =http://www.youtube.com/watch?v=oHg5SJYRHA0; }
（搞怪够了code的创作者甚至没有能够融为一体preSS得当，节省了千字节）
有也是为什么这个code没有在新的浏览器中运行的解释了：他们改变了 Array.prototype.sort 所以它不会返回参照窗口。据我记得，这是去窗口引用的唯一途径，所以这个code现在是一种打破。
I have searched Google for a converter but I did not find anything. Is there any tools available or I must make one to decode my obfuscated JavaScript code ?
I presume there is such a tool but I'm not searching Google with the right keywords. The code is 3 pages long, this is why I need a tools.
Here is an exemple of the code :
<script>([][(![]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+!+[]]+(!![]+[])[+[]]][([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[+!+[]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]()[(!![]+[])[!+[]+!+[]+!+[]]+(+(+[])+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[!+[]+!+[]+!+[]+[+[]]]+(![]+[])[+!+[]]+(![]+[])[!+[]+!+[]]])(([]+[])[([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+
Thank you
This question has already an accepted answer, but I will still post to clear some things up.
When this idea come up, some guy made a generator to encode JavaScript in this way. It is based on doing []["sort"]["call"]()["eval"](/* big blob of code here */). Therefore, you can decode the results of this encoder easily by removing the sort-call-eval part (i.e. the first 1628 bytes). In this case it produces:
if (document.cookie=="6ffe613e2919f074e477a0a80f95d6a1"){ alert("bravo"); }
else{ document.location="http://www.youtube.com/watch?v=oHg5SJYRHA0"; }
(Funny enough the creator of this code was not even able to compress it properly and save a kilobyte)
There is also an explanation of why this code doesn't work in newer browser anymore: They changed Array.prototype.sort so it does not return a reference to window. As far as I remember, this was the only way to get a reference to window, so this code is kind of broken now.
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