动态数组 [英] Dynamic Arrays

问题描述

我刚开始学习C ++所以请原谅我这个简单的问题。我在做什么是从文件中读取的数字，然后试图将它们添加到一个数组。我的问题是你如何增加数组的大小？比如我想也许可以只是做：

I'm just starting to learn C++ so excuse me for this simple question. What I'm doing is reading in numbers from a file and then trying to add them to an array. My problem is how do you increase the size of the array? For example I thought might be able to just do:

#include <iostream>
using namespace std;

int main() {
    double *x;
    x = new double[1];
    x[0]=5;
    x = new double[1];
    x[1]=6;
    cout << x[0] << "," << x[1] << endl;
    return 0;
}

但是，这显然只是覆盖值，5，我最初设置为x [0]和如此输出0,6。我将如何让这个它会输出5,6？

请注意，对于比如我包括我不想从一个在code读数混乱起来文件或code从用户获取数字。在实际应用中我不知道有多大的数组，我需要在编译的时候，所以请不要告诉我只是做一个数组包含两个元素，并将它们设置等于5,6分别。

感谢您的帮助。

But this obviously just overwrites the value, 5, that I initially set to x[0] and so outputs 0,6. How would I make it so that it would output 5,6?

Please realize that for the example I've included I didn't want to clutter it up with the code reading from a file or code to get numbers from a user. In the actual application I won't know how big of an array I need at compile time so please don't tell me to just make an array with two elements and set them equal to 5 and 6 respectively.

Thanks for your help.

推荐答案

您不想直接与阵列工作。考虑使用矢量代替。然后，您可以拨打的push_back 函数添加东西​​到最后，它会自动调整向量为您服务。

You don't want to work with arrays directly. Consider using a vector, instead. Then, you can call the push_back function to add things to the end, and it will automatically resize the vector for you.

#include <iostream>
#include <vector>

int
main() {
    double value;
    std::vector<double> values;

    // Read in values
    while (std::cin >> value) {
        values.push_back(value);
    }

    // Print them back out
    for (std::size_t i(0), len(values.size()); i != len; ++i) {
        std::cout << values[i];
    }
}

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