NSArray的排序按第二个字。 （按姓氏在＆QUOT;姓姓＆QUOT;一种字符串数组） [英] sort nsarray by second word. (by surname in "firstname surname" kind of strings array)

问题描述

我遇到的NSArray像fistname姓字符串。现在我想的字符串数组由第二个字，即按姓氏排序。
我用这个方法

I am having nsarray of strings like "fistname surname". Now I want to sort that strings array by second word i.e. by surname. I used this method

NSArray *sortedArray=[[teachersList allValues] sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)];
    NSLog(@"After %@",sortedArray);

但它第一个字排序数组。

But it sorts array on first word.

和我也有元素或字符串与名字不仅意味着只有第一个字。

And i am also having elements or strings with firstname only means only first word.

那么，如何做到这一点？

So how to do this?

修改

@Janak尼尔默尔

@Janak Nirmal

我修改code是：

while([resultSet next])
{
    [teachersList setObject:[NSString stringWithFormat:@"%@ %@",[resultSet stringForColumn:@"first_name"],[resultSet stringForColumn:@"last_name"]] forKey:[resultSet stringForColumn:@"email_id"]];
    [emailList addObject:[resultSet stringForColumn:@"email_id"]];
    appDelegate.grade=[resultSet stringForColumn:@"grade"];

}

    //NSArray *sortedArrays=[[teachersList allValues] sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)];


   NSArray *sortedArray = [[teachersList allValues] sortedArrayUsingComparator:^NSComparisonResult(id a, id b) {
        NSString *firstTeacher2ndWord = [[[[(Teacher*)a name] componentsSeparatedByString:@" "] objectAtIndex:1] lowercaseString];
        NSString *secondTeacher2ndWord = [[[[(Teacher*)b name] componentsSeparatedByString:@" "] objectAtIndex:1] lowercaseString];
        return [firstTeacher2ndWord compare:secondTeacher2ndWord];
    }];

但我m到处以下错误

but i m getting following error

[__ NSCFString名称]：发送到实例无法识别选择

[__NSCFString name]: unrecognized selector sent to instance

推荐答案

您可以做的有点像，

NSArray *sortedArray = [teacherList sortedArrayUsingComparator:^NSComparisonResult(id a, id b) {
    NSString *firstTeacher2ndWord = [[[[(Teacher*)a name] componentsSeparatedByString:@" "] objectAtIndex:1] lowercaseString];
    NSString *secondTeacher2ndWord = [[[[(Teacher*)b name] componentsSeparatedByString:@" "] objectAtIndex:1] lowercaseString];
    return [firstTeacher2ndWord compare:secondTeacher2ndWord];
}];
//Assuming in above you have atleast 2 words in name 
//i.e. objectAtIndex:1 doesn't fail or you need to put condition 
//there according to your needs

假设下面的模型结构，

Assuming your model structure as below,

@interface Teacher : NSObject

@property (nonatomic,strong) NSString *name;

@end

修改

由于您的[teacherList allValues​​]将直接持有串值，你应该写如下

As your [teacherList allValues] would be directly holding string values you should write it as below

NSArray *sortedArray = [[teachersList allValues] sortedArrayUsingComparator:^NSComparisonResult(id a, id b) {
    NSString *firstTeacher2ndWord = [[[((NSString*)a) componentsSeparatedByString:@" "] objectAtIndex:1] lowercaseString];
    NSString *secondTeacher2ndWord = [[[((NSString*)b) componentsSeparatedByString:@" "] objectAtIndex:1] lowercaseString];
    return [firstTeacher2ndWord compare:secondTeacher2ndWord];
}];

以上code会给你排序的方式对所有值数组直接。

Above code will give you array of all values directly in sorted manner.

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