对于结构数组成员默认值 [英] Default values for arrays members of struct
问题描述
可能重复:结果
<一href=\"http://stackoverflow.com/questions/6647038/intitialzing-an-array-in-a-c-class-and-modifiable-lvalue-problem\">Intitialzing在C ++类和修改的左值问题的一个阵列
作为<一看到href=\"http://stackoverflow.com/questions/1069621/are-members-of-a-c-struct-initialized-to-0-by-default\">this问题,有可能给一个构造函数为结构,使其成员得到默认值。你将如何继续给一个默认值一个结构里的数组中的每个元素。
As seen in this question, it's possible to give a ctor to a struct to make it members get default values. How would you proceed to give a default value to every element of an array inside a struct.
struct foo
{
int array[ 10 ];
int simpleInt;
foo() : simpleInt(0) {}; // only initialize the int...
}
有没有一些方法,使这类似于你会怎么做初始化一个int一行?
Is there some way to make this in one line similar to how you would do to initialize an int?
推荐答案
Thew新的C ++标准有办法做到这一点:
Thew new C++ standard has a way to do this:
struct foo
{
int array[ 10 ];
int simpleInt;
foo() : array{1,2,3,4,5,6,7,8,9,10}, simpleInt(0) {};
};
如果你的编译器不支持此语法的是,你总是可以分配到阵列中的每个元素:
If your compiler does not support this syntax yet, you can always assign to each element of the array:
struct foo
{
int array[ 10 ];
int simpleInt;
foo() : simpleInt(0)
{
for(int i=0; i<10; ++i)
array[i] = i;
}
};
编辑:在pre-2011下1班轮解决方案++需要不同的容器类型,如C ++向量(这是无论如何pferred $ P $),或提振阵列,它可以是的 boost.assign '版
#include <boost/assign/list_of.hpp>
#include <boost/array.hpp>
struct foo
{
boost::array<int, 10> array;
int simpleInt;
foo() : array(boost::assign::list_of(1)(2)(3)(4)(5)(6)(7)(8)(9)(10)),
simpleInt(0) {};
};
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