转换'诠释'到'长'或访问过长阵列“长” [英] converting 'int' to 'long' or accessing too long array with 'long'

问题描述

比方说，我有一个数组，它是足够长的时间访问任何其指数与 INT ，有没有什么办法与<$访问这些数组的索引C $ C>长？而如何在Java处理这种类型的数组？例如：

Let's say I have an array that is long enough to access any of its index with int, is there any way to access the index of such an array with long? And how the Java handle this kind of array? Example:

int[] a = new int[]{1,5,2,4........9,2,1}

假设上面的数组中的 9,2,1 正处在一个超出 INT 的索引范围（2 ³¹ ）。
我将如何访问这些内容？

Assume in the above array that 9,2,1 are at indices that are beyond the range of int (2³¹). How would I access these elements?

推荐答案

您不会 - 数组索引总是在Java的 INT 值。它不允许有更多的数组比 Integer.MAX_VALUE的元素。

You wouldn't - array indexes are always int values in Java. It doesn't allow for an array with more than Integer.MAX_VALUE elements.

数组的长度再由长度字段，它的类型是psented $ P $ INT 。因此，它是不可能有一个长度大于 Integer.MAX_VALUE的创建更大的数组。

The length of an array is represented by the length field, which is of type int. Therefore it is impossible to create an array with a length greater than Integer.MAX_VALUE.

借助规范不显式调用了这一点，但你可以从所涉及的类型推断吧。

The spec doesn't explicitly call this out, but you can infer it from the types involved.

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