函数返回一个对象的索引深深嵌套数组 [英] function to return index of an object in a deeply nested array

问题描述

我需要写也许，仅仅输出对象的索引数组里面，很明显，使用$ .inArray返回此只需在下面的例子中精细的功能。

I need to perhaps write a function that just outputs the index of an object inside an array, obviously, using $.inArray returns this just fine in the example below.

array = ['one', 'two', 'three'];

$.inArray('one', array) // 0

通过更精细的阵列，如何可以找到嵌套的对象的索引？

With a more elaborate array, How can I find the index of the objects nested within?

array = [
    {
        name: 'One', // index??
        data: {
            title: 'Title One',
            content: 'Content One'
        }
    },
    {
        name: 'Two',
        data: {
            title: 'Title Two',
            content: 'Content Two'
        }
    },
    {
        name: 'Three',
        data: {
            title: 'Title Three',
            content: 'Content Three'
        }
    }
];

我听说$ .grep（）方法，的indexOf（）..不知道要使用哪一个只返回对象是

I've heard of the $.grep() method, indexOf() .. not sure which one to use to just return an integer of the index the object is in

推荐答案

您不需要pre-写功能，只需遍历阵列和比较名称属性：

You don't need a pre-written function, just iterate over your array and compare the name property:

function findValue(array, nameWeAreLookingFor) {
    for(var i = 0; i<array.length; i++) {
        if(array[i].name === nameWeAreLookingFor) return i;
    }
    return -1;
}

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