找不到任一列“dbo"或用户定义的函数或聚合“dbo.Splitfn"，或名称不明确 [英] Cannot find either column "dbo" or the user-defined function or aggregate "dbo.Splitfn", or the name is ambiguous

问题描述

大家好，

我使用了下面的分割函数，

I ve used the following split function,

CREATE FUNCTION dbo.Splitfn(@String varchar(8000), @Delimiter char(1))       
returns @temptable TABLE (items varchar(8000))       
 as       
begin       
declare @idx int       
declare @slice varchar(8000)       

select @idx = 1       
    if len(@String)<1 or @String is null  return       

while @idx!= 0       
begin       
    set @idx = charindex(@Delimiter,@String)       
    if @idx!=0       
        set @slice = left(@String,@idx - 1)       
    else       
        set @slice = @String       

    if(len(@slice)>0)  
        insert into @temptable(Items) values(@slice)       

    set @String = right(@String,len(@String) - @idx)       
    if len(@String) = 0 break       
end   
return      

end  

我在查询中使用了这个函数并且它被执行了

and i used this function in a query and it was executed

ALTER PROCEDURE [dbo].[Employees_Delete] 
-- Add the parameters for the stored procedure here
@Id varchar(50)
AS
BEGIN
-- SET NOCOUNT ON added to prevent extra result sets from
-- interfering with SELECT statements.
SET NOCOUNT ON;

-- Insert statements for procedure here

 if exists( select Emp_Id from Employee where Emp_Id=dbo.Splitfn(@Id,','))
begin
    update Employee set Is_Deleted=1 where Emp_Id=dbo.Splitfn(@Id,',')
    select 'deleted' as message
end 
END

但是当我执行我的存储过程给出值时说 (1,2) 我得到了错误

but when i excute my store procedure giving values say (1,2) i got the error

Cannot find either column "dbo" or the user-defined 
function or aggregate "dbo.Splitfn", or the name is ambiguous.

我已经检查了我的表值函数，函数splitfn"在那里，但我不知道出了什么问题?任何建议..

I ve checked my tablevalued functions the function 'splitfn' was there but i dont know what is going wrong? Any suggestions..

推荐答案

这是一个表值函数，但您将其用作标量函数.

It's a table-valued function, but you're using it as a scalar function.

试试:

where Emp_Id IN (SELECT i.items FROM dbo.Splitfn(@Id,',') AS i)

但是...也可以考虑将您的函数更改为内联 TVF，因为它会表现得更好.

But... also consider changing your function into an inline TVF, as it'll perform better.

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