在 SQL Server 2008 中用逗号分割字符串 [英] Split string by comma in SQL Server 2008
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问题描述
有两个字符串 a
和 b
a
字符串包含逗号.我想用逗号分割一个字符串,然后遍历每个元素.
The a
string contains comma. I would like to split the a string by comma, then go through every element .
如果 b
字符串包含任何由逗号分隔的元素将返回 0
IF the b
string contains any element which split by comma will return 0
(eg: a = "4,6,8"
; b = "R3799514"
因为 b
字符串包含 4 所以返回0)
(e.g: a = "4,6,8"
; b = "R3799514"
because the b
string contains 4 so return 0)
如何用存储过程实现这一点?提前致谢!
How to achieve this with a stored procedure? Thanks in advance!
我看到了一个拆分函数:
I have seen a split function:
CREATE FUNCTION dbo.Split(@String varchar(8000), @Delimiter char(1))
returns @temptable TABLE (items varchar(8000))
as
begin
declare @idx int
declare @slice varchar(8000)
select @idx = 1
if len(@String)<1 or @String is null return
while @idx!= 0
begin
set @idx = charindex(@Delimiter,@String)
if @idx!=0
set @slice = left(@String,@idx - 1)
else
set @slice = @String
if(len(@slice)>0)
insert into @temptable(Items) values(@slice)
set @String = right(@String,len(@String) - @idx)
if len(@String) = 0 break
end
return
end
select top 10 * from dbo.split('Chennai,Bangalore,Mumbai',',')
推荐答案
以下操作 -
DECLARE @A VARCHAR (100)= '4,5,6'
DECLARE @B VARCHAR (100)= 'RXXXXXX'
DECLARE @RETURN_VALUE BIT = 1 --DEFAULT 1
SELECT items
INTO #STRINGS
FROM dbo.split(@A,',')
IF EXISTS(SELECT 1 FROM #STRINGS S WHERE CHARINDEX(items, @B) > 0)
SET @RETURN_VALUE = 0
PRINT @RETURN_VALUE
DROP TABLE #STRINGS
您也可以使用 CONTAINS 代替 CHARINDEX -
You can also use CONTAINS instead of CHARINDEX -
IF EXISTS(SELECT 1 FROM #STRINGS S WHERE CONTAINS(items, @B))
SET @RETURN_VALUE = 0
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