SQL Server 2008 R2:模式匹配字符串反之亦然 [英] SQL Server 2008 R2: Pattern matching string vice versa

问题描述

我有下表:

表格:

CREATE TABLE str_matching
(
    colstr varchar(200)
);

插入数据:

INSERT INTO str_matching VALUES('5sXYZA1010B')
INSERT INTO str_matching VALUES('A1010B')
INSERT INTO str_matching VALUES('AMZ103B15K')
INSERT INTO str_matching VALUES('B15K')
INSERT INTO str_matching VALUES('XC101')
INSERT INTO str_matching VALUES('C101')
INSERT INTO str_matching VALUES('502KMD1FZ10009L')
INSERT INTO str_matching VALUES('FZ10009L')
INSERT INTO str_matching VALUES('A9L')
INSERT INTO str_matching VALUES('XZ049L')
INSERT INTO str_matching VALUES('LM101')
INSERT INTO str_matching VALUES('9001')
INSERT INTO str_matching VALUES('9001A')

预期输出:我只想显示那些有重复条目的记录，如果一个字符串与任何字符串的最后一部分匹配，那么我认为是重复的.

Expected Output: I want to display only those records that has duplicate entries, if one string match last part of any string then I am considering as duplicate.

场景:1

例如:我有两个字符串

1. 5sXYZA1010B
2. A1010B

与第一个字符串末尾匹配的第二个字符串，因此要显示此类记录.

2nd string which is matching at end of 1st string, so want to display such records.

场景:2

例如:我有两个字符串

1. 9001
2. 9001A

第一个字符串与第二个字符串的第一个匹配，所以想显示这样的记录.

1st string which is matching at first of 2nd string, so want to display such records.

注意:字符串的长度不固定，可以任意匹配.

Note: Length of string's are not fixed, it can be match at any point.

预期结果:

colstr              
--------------------
5sXYZA1010B         
A1010B              
AMZ103B15K          
B15K                
XC101               
C101                
502KMD1FZ10009L     
FZ10009L    
9001
9001A   

注意:需要检查反之亦然模式匹配.

Note: Need to check the vice versa pattern matching.

根据 Martin Smith 代码，我已修改为:>

As per Martin Smith code, I have modified to:

SELECT DISTINCT CA.colstr
FROM   str_matching s1
       JOIN str_matching s2
         ON s1.colstr <> s2.colstr
            AND s2.colstr LIKE '%' + s1.colstr 
            OR s1.colstr LIKE '%' + s2.colstr
       CROSS APPLY (VALUES(s1.colstr),
                          (s2.colstr)) CA(colstr) 

但无法获得给定的字符串集.

But unable to get the given set of strings.

推荐答案

这对我有用:

SELECT DISTINCT CA.colstr
FROM str_matching s1 JOIN
 str_matching s2
 ON s1.colstr <> s2.colstr AND
    (s1.colstr LIKE s2.colstr + '%' OR
     s2.colstr LIKE '%'+ s1.colstr 
    ) CROSS APPLY
 (VALUES(s1.colstr), (s2.colstr)) as CA(colstr) ;

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