是reinter pret_cast到C数组非法C ++ 11？ [英] Is reinterpret_cast to C-style array illegal C++11?

问题描述

为什么以下code皱眉？

Why is the following code frowned upon?

double d[4] = {0,1,2,3};
reinterpret_cast<double[2]>(d);

海湾合作委员会声明它的类型双*'的无效强制转换为类型'双[2]和铿锵声明 reinter $ P $从pt_cast双*'到'双[2]是不允许

现在的情况下，意图不是很明显，我想这code返回一个double [2]包含{0,1}，pretty很像 reinter pret_cast＆LT;双* GT;（四）会。 （因此，我知道它会使用指针工作，所以这不是我问的）

Now in case the intent is not obvious, I would like this code to return a double[2] that contains {0,1}, pretty much like a reinterpret_cast<double*>(d) would. (Hence I know it would work with pointers, so that's not what I'm asking)

推荐答案

这两种编译器是正确的。

Both compilers are correct.

reinter pret_cast 不是锤子，它是一个功能强大的precision工具。 reinter pret_cast 的所有用途都涉及到至少一个指针或引用类型作为源或目的，除了标识整体转换的退化情况（即 reinter pret_cast 从 INT 到 INT 是允许和不执行任何操作。）

reinterpret_cast is not a hammer, it's a powerful precision tool. All uses of reinterpret_cast have to involve at least one pointer or reference type as the source or as the destination, except for the degenerate case of an identity integral conversion (i.e. reinterpret_cast from int to int is allowed and does nothing.)

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