R中参差不齐的数据框中按年份加权平均 [英] Weighted Average by Year in ragged data frame in R
问题描述
我有一个包含八个变量的数据框.我想计算年度加权平均百分比损失的平均平均值.但是,并不是我的数据集中每年都存在所有变量.这样做的最简单方法是什么?下面包括一个示例数据集和最终所需的输出.
I have a data frame with eight variables. I would like to calculate the average mean of annual weighted average percent loss. However, not all variables exist for each year in my dataset. What would be the simplest method to do so? Included below is a sample dataset and final desired output.
谢谢!
样本数据集
Fruit.Type Year Primary.Wgt Primary.Loss.PCT Retail.Wgt Retail.Loss.PCT Cons.Wgt Cons.Loss.PCT
Oranges.F 1970 16.16 3.0 15.68 11.6 13.86 36.0
Oranges.F 1971 15.73 3.0 15.26 11.6 13.49 36.0
Oranges.F 1972 14.47 3.0 14.04 11.6 12.41 36.0
Oranges.F 1973 14.43 3.0 14.00 11.6 12.38 36.0
Tangerines.F 1971 2.34 5.0 2.22 20.4 1.80 52.0
Tangerines.F 1972 2.06 5.0 1.96 20.4 1.60 52.0
Tangerines.F 1973 2.07 5.0 1.97 20.4 1.60 52.0
Grapefruit.F 1970 8.22 3.0 7.97 12.8 6.90 20.0
Grapefruit.F 1971 8.55 3.0 8.29 12.8 7.20 20.0
Grapefruit.F 1972 8.56 3.0 8.31 12.8 7.20 20.0
Grapefruit.F 1973 8.57 3.0 8.31 12.8 7.20 20.0
所需的输出(在 excel 中计算)输出(加权平均百分比损失)
desired output (calc'd in excel) Output (weighted average percent loss)
Year Primary.Loss.PCT Retail.Loss.PCT Cons.Loss.PCT
1970 3.00 11.82 11.98
1971 3.00 14.95 32.16
1972 3.16 14.66 31.78
1973 3.17 14.68 31.77
Mean 3.08 14.03 26.92
Standard Error 0.048 0.737 4.980
推荐答案
有很多方法.我更喜欢通过 data.table
.首先将您的数据转换为data.table
:
There are many ways. I would prefer via a data.table
.
First convert your data into a data.table
:
require(data.table) #tested in data.table 1.9.4
setDT(mydata)
> mydata
Fruit.Type Year Primary.Wgt Primary.Loss.PCT Retail.Wgt Retail.Loss.PCT
1: Oranges.F 1970 16.16 3 15.68 11.6
2: Oranges.F 1971 15.73 3 15.26 11.6
3: Oranges.F 1972 14.47 3 14.04 11.6
4: Oranges.F 1973 14.43 3 14.00 11.6
5: Tangerines.F 1971 2.34 5 2.22 20.4
6: Tangerines.F 1972 2.06 5 1.96 20.4
7: Tangerines.F 1973 2.07 5 1.97 20.4
8: Grapefruit.F 1970 8.22 3 7.97 12.8
9: Grapefruit.F 1971 8.55 3 8.29 12.8
10: Grapefruit.F 1972 8.56 3 8.31 12.8
11: Grapefruit.F 1973 8.57 3 8.31 12.8
Cons.Wgt Cons.Loss.PCT
1: 13.86 36
2: 13.49 36
3: 12.41 36
4: 12.38 36
5: 1.80 52
6: 1.60 52
7: 1.60 52
8: 6.90 20
9: 7.20 20
10: 7.20 20
11: 7.20 20
然后让我们进行基于组的聚合:
Then let's do the group-based aggregation:
mydata2 <- mydata[,list(
Primary.Loss.PCT=sum(Primary.Wgt*Primary.Loss.PCT)/sum(Primary.Wgt),
Retail.Loss.PCT=sum(Retail.Wgt*Retail.Loss.PCT)/sum(Retail.Wgt),
Cons.Loss.PCT=sum(Cons.Wgt*Cons.Loss.PCT)/sum(Cons.Wgt)),
by=Year]
> mydata2
Year Primary.Loss.PCT Retail.Loss.PCT Cons.Loss.PCT
1: 1970 3.000000 12.00440 30.68208
2: 1971 3.175808 12.74412 32.15829
3: 1972 3.164209 12.71970 31.77558
4: 1973 3.165138 12.72471 31.76959
最后,我们计算均值和 se:
Finally, we compute the mean and se:
> colMeans(mydata2[,-1,with=FALSE])
Primary.Loss.PCT Retail.Loss.PCT Cons.Loss.PCT
3.126289 12.548234 31.596386
> require(plotrix); std.error(mydata2[,-1,with=FALSE])
Primary.Loss.PCT Retail.Loss.PCT Cons.Loss.PCT
0.04217833 0.18135513 0.31804132
我希望我理解了你的计算逻辑.但是,最终输出与您的不同.无论如何,您可以根据自己的需要调整代码.
I hope I had understand the logic of your computation. However, the final output is different from yours. Anyway, you may adjust the code to follow your needs.
这篇关于R中参差不齐的数据框中按年份加权平均的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!