C# 处理标准输入 [英] C# Process Standard Input

问题描述

我目前正在尝试通过命令行与网络文件夹断开连接，并使用以下代码:

I am currently trying to disconnect from a network folder through the command line and am using the following code:

System.Diagnostics.Process process2 = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
startInfo.FileName = "cmd.exe";
startInfo.Arguments = "/C NET USE F: /delete";
startInfo.RedirectStandardError = true;
startInfo.RedirectStandardInput = true;
startInfo.RedirectStandardOutput = true;
startInfo.UseShellExecute = false;
startInfo.CreateNoWindow = true;
process2.StartInfo = startInfo;
process2.Start();

StreamWriter sw = process2.StandardInput;
sw.WriteLine("Y");
sw.Close();

process2.WaitForExit();
process2.Close();

有时，我收到消息可以继续断开连接并强制关闭它们吗?(是/否)[否]"，对此我想回复是"，但我似乎对此有疑问在职的.

Occasionally, I get the message "Is it ok to continue disconnecting and force them closed? (Y/N) [N]", to which I want to reply "Y", but I seem to be having issues with that working.

有谁知道为什么我的代码没有在标准输入中输入Y"?

Does anyone know why my code is not inputting "Y" to standard input?

推荐答案

使用下面 代码 得到消息可以继续断开连接并强制关闭它们吗?(Y/N) [N]"，回复Y"

Use below code to get the message "Is it ok to continue disconnecting and force them closed? (Y/N) [N]", to which reply "Y"

static void Main(string[] args)
{
    System.Diagnostics.Process process2 = new System.Diagnostics.Process();
    System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
    startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
    startInfo.FileName = "cmd.exe";
    startInfo.Arguments = "/C NET USE F: /delete";
    startInfo.RedirectStandardError = true;
    startInfo.RedirectStandardInput = true;
    startInfo.RedirectStandardOutput = true;
    startInfo.UseShellExecute = false;
    startInfo.CreateNoWindow = true;
    process2.StartInfo = startInfo;
    process2.Start();

    Read(process2.StandardOutput);
    Read(process2.StandardError);

    while (true)
        process2.StandardInput.WriteLine("Y");

}

private static void Read(StreamReader reader)
{
    new Thread(() =>
    {
        while (true)
        {
            int current;
            while ((current = reader.Read()) >= 0)
                Console.Write((char)current);
        }
    }).Start();
}

我认为这可能对您有所帮助..

I think this may help you..

这篇关于C# 处理标准输入的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！