在不访问代码的情况下删除 Python 中所有子进程的输出 [英] Remove output of all subprocesses in Python without access to code

问题描述

在 Python 中我正在使用

In Python I'm using

sys.stdout = None 

在一些我无法控制的电话之前.这些调用可能会调用一些写入标准输出的子进程.

before some calls that I don't control. These calls may call some subprocesses that write to stdout.

如何避免此子进程调用写入标准输出?

How can I avoid this subprocesses calls to write to stdout?

同样，我没有调用子进程的代码的所有权.似乎 subprocess.Popen(和类似的)不尊重 sys.stdout.

Again, I don't have ownership of the code that calls the subprocess. It seems subprocess.Popen (and similar) doesn't honor sys.stdout.

推荐答案

您可以使用抑制 stdout 和 stderr<的自定义函数替换 subprocess.Popen/代码>:

You could replace subprocess.Popen with a custom function that suppresses stdout and stderr:

import subprocess
import inspect

def Popen(*args, **kwargs):
    sig = inspect.signature(real_popen)
    bound_args = sig.bind(*args, **kwargs).arguments
    bound_args['stdout'] = subprocess.DEVNULL
    bound_args['stderr'] = subprocess.DEVNULL
    return real_popen(**bound_args)

real_popen = subprocess.Popen
subprocess.Popen = Popen

警告:

如果您的代码试图读取进程的输出，它将失败.

If you have code that attempts to read the process's output, it will fail.

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