仅手动冲洗 cout [英] Flush cout manually only

问题描述

据我所知，将 std::endl 流式传输到 std::cout 会刷新它.我认为这种行为对大多数应用程序都有意义.

As far as I know streaming std::endl into std::cout will flush it. I get that that behavior makes sense for most applications.

我的问题是我有一些使用多个 std::endl 的输出，因此刷新了输出.这对我的程序的性能来说真的很糟糕，而且还会导致很多图形故障，因为我经常跳来跳去.

My problem is that I have some output that uses multiple std::endl's and therefore flushes the output. This is really bad for the performance of my program and also causes a lot of graphical glitches since I am jumping around quite a lot.

所以我的问题是我是否可以告诉 std::cout 等待下一次刷新，直到我明确调用 std::cout.flush() 或流 std::flush 到 std::cout.
如果这是可能的，我还想知道我如何才能扭转这种情况，因为这对我来说并不总是有意义.

So my question is if I can tell std::cout to wait with the next flush until I explicitly call std::cout.flush() or stream std::flush into std::cout.
If this is possible I'd also like to know how I then can reverse that since it does not always make sense for me.

推荐答案

使用 std::cout <<'\n' 而不是 std::endl.这避免了每行之后的刷新.std::endl 将始终刷新，因为这是它的目的.没有选项可以禁用该行为.但是，根本不需要使用 std::endl.最终，您无法避免所有刷新，因为 std::cout 的缓冲区是有限的，因此最终，无论您是否使用 std::endl，输出都将被刷新或 '\n'.

Use std::cout << '\n' instead of std::endl. This avoids the flush after every line. std::endl will always flush, since that is its purpose. There's no option to disable that behavior. However, there's no requirement to use std::endl at all. Ultimately, you can't avoid all flushing as the buffer for std::cout is finite, so eventually, the output will be flushed regardless if you use std::endl or '\n'.

如果你想增加标准输出的缓冲区大小，你可以尝试增加 cout 的缓冲区.

If you want to increase the buffer size for standard output, you could try increase buffer for cout.

这篇关于仅手动冲洗 cout的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！