数组中的C结构 [英] Array in C struct

问题描述

我想有一个结构两个阵列，这是在启动初始化，但还需要进一步的编辑。我需要的结构的三个实例，这样我可以索引到一个特定的结构和修改如我所愿。这可能吗？

这是我想我可以做的，但我得到的错误：

 结构potNumber {
    int数组[20] = {[0 ... 19] = 10};
    字符* theName [] = {一半对一半，杏仁，树莓，香草，...};
} APOT [3];
 

然后我访问结构如下：

 的printf（一些语句％S，APOT [0] .array [0]）;
 APOT [0] .theName [3];
 ...
 

解决方案

该结构本身没有数据。您需要创建的结构类型的对象和设置的对象...

 结构potNumber {
    int数组[20];
    字符* theName [42];
};/ *我喜欢从对象创建的类型定义分离* /
结构potNumber APOT [3];
/ *用C99编译器，你可以使用指定的初始值'* /
结构potNumber bPot = {{[7] = 7，[3] = -12}，{[4] =四，[6] =六}};对于（I = 0; I＆小于20;我++）{
  APOT [0] .array [我] =我;
}
APOT [0] .theName [0] =一半对一半;
APOT [0] .theName [1] =杏仁;
APOT [0] .theName [2] =树莓;
APOT [0] .theName [3] =香草;
/ * ... * /对于（I = 0; I＆小于20;我++）{
  APOT [2] .array [I] = 42 + I;
}
APOT [2] .theName [0] =一半对一半;
APOT [2] .theName [1] =杏仁;
APOT [2] .theName [2] =树莓;
APOT [2] .theName [3] =香草;
/ * ... * /
 

I want to have two arrays in a struct, which are initialized at start but need editing further on. I need three instances of the struct, so that I can index into a specific struct and modify as I wish. Is it possible?

This is what I thought I could do but I get errors:

struct potNumber{
    int array[20] = {[0 ... 19] = 10};
    char *theName[] = {"Half-and-Half", "Almond", "Rasberry", "Vanilla", …};
} aPot[3];

Then I access the structs as follows:

 printf("some statement %s", aPot[0].array[0]);
 aPot[0].theName[3];
 …

解决方案

The struct themselves do not have data. You need to create objects of the struct type and set the objects ...

struct potNumber {
    int array[20];
    char *theName[42];
};

/* I like to separate the type definition from the object creation */
struct potNumber aPot[3];
/* with a C99 compiler you can use 'designated initializers' */
struct potNumber bPot = {{[7] = 7, [3] = -12}, {[4] = "four", [6] = "six"}};

for (i = 0; i < 20; i++) {
  aPot[0].array[i] = i;
}
aPot[0].theName[0] = "Half-and-Half";
aPot[0].theName[1] = "Almond";
aPot[0].theName[2] = "Rasberry";
aPot[0].theName[3] = "Vanilla";
/* ... */

for (i = 0; i < 20; i++) {
  aPot[2].array[i] = 42 + i;
}
aPot[2].theName[0] = "Half-and-Half";
aPot[2].theName[1] = "Almond";
aPot[2].theName[2] = "Rasberry";
aPot[2].theName[3] = "Vanilla";
/* ... */

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