String 类 compareTo() 方法返回什么 [英] What does the String classes compareTo() method return

问题描述

在 Oracle 的 Java API 中 website: "compareTo Returns: "如果参数字符串等于这个字符串，则值为 0；如果此字符串按字典顺序小于字符串参数，则为小于 0 的值；如果此字符串按字典顺序大于字符串参数，则为大于 0 的值." "

In the Java API on oracles website: "compareTo Returns: "the value 0 if the argument string is equal to this string; a value less than 0 if this string is lexicographically less than the string argument; and a value greater than 0 if this string is lexicographically greater than the string argument." "

这是一个 if 语句:

Here is an if statement:

String a = "abd";
String b = "abc";

if(a.compareTo(b) >= 1)

返回真因为字符串 a 更大，按字典顺序排列.

returns true since string a is greater, lexicographically.

我的问题是，compareTo 是否总是返回 0、1 或 -1?或者它是否返回字符串大于或小于字符串参数的实际数量.

My question is, does the compareTo always return a 0, 1, or -1? or does it return the actual amount that the string is greater than or less than the string argument.

那么在上面的 if 语句中，由于 "abd" 比 "abc" 大 1，所以它返回 1 吗?

So in the above if statement, since "abd" is one greater than "abc" is it returning 1?

推荐答案

就您而言，不知道 compareTo 返回值的大小是多少，只知道符号.在实践中，大多数 compareTo 实现将返回 -1、0 或 1，但契约明确规定了正数或负数，您应该相应地编写代码(例如，使用 int compare = a.compareTo(b); if(compare > 0) {...} else...).

As far as you're concerned, there's no telling what the magnitude of the compareTo return value is, just the sign. In practice, most compareTo implementations will return -1, 0, or 1, but the contract specifically says positive or negative, and you should write your code accordingly (e.g., using int compare = a.compareTo(b); if(compare > 0) {...} else...).

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