Collection类的sort()方法如何调用Comparable的compareTo()? [英] How does the sort() method of the Collection class call the Comparable's compareTo()?

查看:160
本文介绍了Collection类的sort()方法如何调用Comparable的compareTo()?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

假设我要对Employee个对象的列表进行排序:

Suppose I want to sort a list of Employee objects:

Employee emp1 = new Employee("Abhijit", 10);
Employee emp2 = new Employee("Aniket", 5);
Employee emp3 = new Employee("Chirag", 15);

List<Employee> employees = new ArrayList<Employee>();
employees.add(emp1);
employees.add(emp2);
employees.add(emp3);
Collections.sort(employees);
System.out.println("sorted List is: "+employees);

我的Employee类实现了Comparable,因此它必须重写compareTo()方法.
而且我必须在compareTo()方法中编写排序逻辑.

And my Employee class implements Comparable, therefore it must override the compareTo() method.
And I have to write my sorting logic in the compareTo() method.

class Employee implements Comparable<Employee>
{
    String name;
    int empId;
    public Employee(String name, int empId)
    {
        this.name= name;
        this.empId = empId;
    }
    public String getName()
    {
        return name;
    }
    public void setName(String name)
    {
        this.name = name;
    }
    public int getEmpId()
    {
        return empId;
    }
    public void setEmpId(int empId)
    {
        this.empId = empId;
    }
    @Override
    public int compareTo(Employee e)
    {
        // TODO Auto-generated method stub
        return this.empId > e.empId ? 1 : (this.empId < e.empId ? -1 : 0);
        //return 0;
    }
    @Override
    public String toString()
    {
        return String.valueOf(empId);
    }
}

sort()如何在内部调用compareTo()方法?

How does sort() call the compareTo() method internally?

推荐答案

请参阅打开的jdk源代码.我想这会有所帮助.

Please see open jdk source codes. I guess it helps.

集合排序调用Arrays.sort

Collections sort calls Arrays.sort

Arrays.sort调用Arrays.mergeSort,您的答案在第1157行.

Arrays.sort calls Arrays.mergeSort and your answer is on the line 1157.

1145
1146    private static void More ...mergeSort(Object[] src,
1147                                  Object[] dest,
1148                                  int low,
1149                                  int high,
1150                                  int off) {
1151        int length = high - low;
1152
1153        // Insertion sort on smallest arrays
1154        if (length < INSERTIONSORT_THRESHOLD) {
1155            for (int i=low; i<high; i++)
1156                for (int j=i; j>low &&
1157                         ((Comparable) dest[j-1]).compareTo(dest[j])>0; j--)
1158                    swap(dest, j, j-1);
1159            return;
1160        }
1161
1162        // Recursively sort halves of dest into src
1163        int destLow  = low;
1164        int destHigh = high;
1165        low  += off;
1166        high += off;
1167        int mid = (low + high) >>> 1;
1168        mergeSort(dest, src, low, mid, -off);
1169        mergeSort(dest, src, mid, high, -off);
1170
1171        // If list is already sorted, just copy from src to dest.  This is an
1172        // optimization that results in faster sorts for nearly ordered lists.
1173        if (((Comparable)src[mid-1]).compareTo(src[mid]) <= 0) {
1174            System.arraycopy(src, low, dest, destLow, length);
1175            return;
1176        }
1177
1178        // Merge sorted halves (now in src) into dest
1179        for(int i = destLow, p = low, q = mid; i < destHigh; i++) {
1180            if (q >= high || p < mid && ((Comparable)src[p]).compareTo(src[q])<=0)
1181                dest[i] = src[p++];
1182            else
1183                dest[i] = src[q++];
1184        }
1185    }

这篇关于Collection类的sort()方法如何调用Comparable的compareTo()?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆