同时标记多个字符串 [英] Tokenizing multiple strings simultaneously

问题描述

假设我有三个 c 风格的字符串，char buf_1[1024]、char buf_2[1024] 和 char buf_3[1024]>.我想标记它们，并使用所有三个中的第一个标记执行操作，然后使用所有三个中的第二个标记执行相同操作，等等.显然，我可以调用 strtok 并从每次我想要一个新令牌时开始.或者，对所有令牌进行预处理，将它们放入三个数组中，然后从那里开始，但如果有的话，我想要一个更简洁的解决方案.

Say I have three c-style strings, char buf_1[1024], char buf_2[1024], and char buf_3[1024]. I want to tokenize them, and do things with the first token from all three, then do the same with the second token from all three, etc. Obviously, I could call strtok and loop through them from the beginning each time I want a new token. Or alternatively, pre-process all the tokens, stick them into three arrays and go from there, but I'd like a cleaner solution, if there is one.

推荐答案

听起来您想要 strtok 的可重入版本，strtok_r 它使用第三个参数来保存它在字符串中的位置，而不是函数中的静态变量.

It sounds like you want the reentrant version of strtok, strtok_r which uses a third parameter to save its position in the string instead of a static variable in the function.

这是一些示例骨架代码:

Here's some example skeleton code:

char buf_1[1024], buf_2[1024], buf_3[1024];
char *save_ptr1, *save_ptr2, *save_ptr3;
char *token1, *token2, *token3;

// Populate buf_1, buf_2, and buf_3

// get the initial tokens
token1 = strtok_r(buf_1, " ", &save_ptr1);
token2 = strtok_r(buf_2, " ", &save_ptr2);
token3 = strtok_r(buf_3, " ", &save_ptr3);

while(token1 && token2 && token3) {
    // do stuff with tokens

    // get next tokens
    token1 = strtok_r(NULL, " ", &save_ptr1);
    token2 = strtok_r(NULL, " ", &save_ptr2);
    token3 = strtok_r(NULL, " ", &save_ptr3);
}

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