如何将星期六指定为 strtotime 的工作日 [英] How to specify saturday as a week day for strtotime

问题描述

我需要在当前日期的基础上增加 2 个工作日.我打算用 strtotime 来做，但 strtotime 的工作日不包括星期六.

I need to add 2 business days to the current date. I was going to use strtotime for it, but strtotime's weekdays don't include saturday.

$now = date("Y-m-d H:i:s");
$add = 2;
$format = "d.m.Y";
if(date('H') < 12) {
    $add = 1;
}
$date = strtotime($now . ' +'.$add.' weekdays');
echo date($format, $date);

如果您在星期五运行它，它将输出星期二.但它实际上应该在星期一返回.

This would output Tuesday if you run it on Friday. But it actually should return Monday.

如何将星期六添加为工作日?

How can i add Saturday as a weekday?

推荐答案

从特定日期+偏移天数开始获取下一个工作日:

Get next business day from specific date + number of day offset:

function get_next_business_date($from, $days) {
    $workingDays = [1, 2, 3, 4, 5, 6]; # date format = N (1 = Monday, ...)
    $holidayDays = ['*-12-25', '*-01-01', '2013-12-24']; # variable and fixed holidays

    $from = new DateTime($from);
    while ($days) {
        $from->modify('+1 day');
        if (!in_array($from->format('N'), $workingDays)) continue;
        if (in_array($from->format('Y-m-d'), $holidayDays)) continue;
        if (in_array($from->format('*-m-d'), $holidayDays)) continue;
        $days--;
    }
    return $from->format('Y-m-d'); #  or just return DateTime object
}

print_r( get_next_business_date('today', 2) );

演示

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