将私有结构设置为返回值 [英] Setting a private struct as a return value

问题描述

对于类赋值，我们需要在类中有一个私有结构，但我们需要有相同的结构作为返回值(而不是指向它的指针).一些类似的东西:

For a class assignment, we are required to have a private struct in a class, but we need to have the same struct as a return value (not a pointer to it). Something along these lines:

private:
    struct Employee 
    {
        int id;
        string name;    
    };

public:
    struct Employee find(int key);

这是否可以仅使用 STL?

Is this possible using exclusively the STL?

推荐答案

可以做到，但意义不大，因为接口应该是公开的.

It can be done but does not make great sense because the interface should be public.

例如

#include <iostream>
#include <string>

struct C
{
private:
    struct Employee 
    {
        int id;
        std::string name;    
    };

    Employee e = { 1, "First" };

public:
    Employee find(int key) const
    {
        return key == e.id ? e : Employee {};
    }
};

int main() 
{
    C c;

    auto e = c.find( 1 );

    std::cout << e.name << std::endl;

    return 0;
}

程序输出为

First

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