打字稿:如何从继承的静态属性返回子类类型? [英] Typescript: how to return subclass type from inherited static property?

问题描述

class BaseDoc {
    static Collection;  
    static find(){
        // which is expected to return an instance of SubDoc when run SubDoc.find()
        return this.Collection.find();  
    }
}

class SubDoc extends BaseDoc {}

我希望的是:当运行 SubDoc.find() 时，应用程序知道返回值的类型是 SubDoc 的实例而不是 BaseDoc.

What I hope is: When running SubDoc.find(), the app knows the type of the return value to be an instance of SubDoc rather than BaseDoc.

我怎样才能做到这一点?

How can I achieve that?

推荐答案

您可以创建 find 的通用版本，该版本会将 this 参数推断为调用它的类，并使用 InstanceType 从类类型中提取实际实例类型:

You can create a generic version of find that will have the this parameter inferred to the type of the class it's being called on, and use InstanceType<T> to extract the actual instance type from the class type:

class BaseDoc {
    static Collection: any;
    static find<T extends typeof BaseDoc>(this: T): InstanceType<T> {
        // which is expected to return an instance of SubDoc when run SubDoc.find()
        return this.Collection.find();
    }
}

class SubDoc extends BaseDoc {

}

SubDoc.find() // return SubDoc

或者您可以强制派生类定义适当类型的通用Collection成员:

Or you can mandate that the derived class defines a generic Collection member of the appropriate type:

class Collection<T> {
    find(): T {
        return null as any // dummy imeplmentation
    }
}
type GetCollectionItem<T extends Collection<any>> = T extends Collection<infer U> ? U: never;

class BaseDoc {
    static Collection: Collection<BaseDoc>;
    static find<T extends { new (... args: any[]) : any, Collection: Collection<any> }>(this: T):  GetCollectionItem<T['Collection']> {
        // which is expected to return an instance of SubDoc when run SubDoc.find()
        return this.Collection.find();
    }
}

class SubDoc extends BaseDoc {
    static Collection: Collection<SubDoc>;
}

SubDoc.find() // return SubDoc

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