python正则表达式查找以数字为中心的子字符串 [英] python regex find substrings centered with numbers
问题描述
我有一个字符串.我想将字符串切割成子字符串,其中包含一个包含数字的单词,两边由(最多)4 个单词包围.如果子串重叠,它们应该合并.
I have a string. I want to cut the string up into substrings that include a number-containing word surrounded by (up to) 4 words on either side. If the substrings overlap they should combine.
Sampletext = "by the way I know 54 how to take praise for 65 excellent questions 34 thank you for asking appreciated."
re.findall('(\s[*\s]){1,4}\d(\s[*\s]){1,4}', Sampletext)
desired output = ['the way I know 54 how to take praise', 'to take praise for 65 excellent questions 34 thank you for asking']
推荐答案
重叠匹配:使用 Lookaheads
这样做:
subject = "by the way I know 54 how to take praise for 65 excellent questions 34 thank you for asking appreciated."
for match in re.finditer(r"(?=((?:\b\w+\b ){4}\d+(?: \b\w+\b){4}))", subject):
print(match.group(1))
什么是词?
输出取决于您对单词的定义.在这里,总而言之,我允许使用数字.这会产生以下输出.
The output depends on your definition of a word. Here, in a word, I have allowed digits. This produces the following output.
输出(允许在单词中使用数字)
the way I know 54 how to take praise
to take praise for 65 excellent questions 34 thank
for 65 excellent questions 34 thank you for asking
选项 2:单词中没有数字
subject = "by the way I know 54 how to take praise for 65 excellent questions 34 thank you for asking appreciated."
for match in re.finditer(r"(?=((?:\b[a-z]+\b ){4}\d+(?: \b[a-z]+\b){4}))", subject, re.IGNORECASE):
print(match.group(1))
输出 2
the way I know 54 how to take praise
选项 3:扩展到四个不间断的非数字单词
根据您的评论,此选项将扩展到枢轴的左侧和右侧,直到匹配四个不间断的非数字单词.逗号被忽略.
Based on your comments, this option will extend to the left and right of the pivot until four uninterrupted non-digit words are matched. Commas are ignored.
subject = "by the way I know 54 how to take praise for 65 excellent questions 34 thank you for asking appreciated. One Two Three Four 55 Extend 66 a b c d AA BB CC DD 71 HH DD, JJ FF"
for match in re.finditer(r"(?=((?:\b[a-z]+[ ,]+){4}(?:\d+ (?:[a-z]+ ){1,3}?)*?\d+.*?(?:[ ,]+[a-z]+){4}))", subject, re.IGNORECASE):
print(match.group(1))
输出 3
the way I know 54 how to take praise
to take praise for 65 excellent questions 34 thank you for asking
One Two Three Four 55 Extend 66 a b c d
AA BB CC DD 71 HH DD, JJ FF
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