找到两个向量的平均平均配对 [英] Finding the average mean pairing of two vector
问题描述
我有一个整数变量 res
,它存储从一个向量到另一个向量的每个元素的总和,其中的结果被跟踪.其中 length(a) = 10
和 length(b) = 10 或 15 或任何长度 >长度(a).
I have an integer variable res
which stores the sum of of each element from one vector to another vector where the results are kept track. Where length(a) = 10
and length(b) = 10 or 15 or any length > length(a).
a <- 1:10
b <- 1:15
nm <- outer(seq_along(a), seq_along(b), FUN = function(x, y) sprintf('a%d + b%d', x, y))
res <- setNames(c(outer(a,b,`+`)), nm)
res
# a1+b1 a2+b1 a3+b1 a4+b1 a5+b1 ... a6+b15 a7+b15 a8+b15 a9+b15 a10+b15
# 2 3 4 5 6 ... 21 22 23 24 25
如何找到每个唯一对的最大值?假设 a10 + b15 = 25
是最大值,那么在第二次迭代中,任何包含 a10
或 b15
的对都被省略.重复这个过程,直到没有唯一的对.
How can I find the maximum of each unique pair? Let say a10 + b15 = 25
is the maximum, then in the second iteration, any pair containing a10
or b15
are omitted. This process is repeated until no unique pairs are left.
如何修改下面函数中的 if
语句以找到最大唯一配对的平均值?还是有其他方法?
How can I modify the if
statement in the below function to find the mean of the maximum unique pairing? Or there is another way round?
f1 <- function(x) {
x1 <- max(x)
repeat {
x <- x[!grepl(sub(" \\+ ", "|", names(which.max(x))), names(x))]
x1 <- c(x1, max(x))
if(length(x)==1) break
}
return(list(x, mean(x1)))
}
注意:这个问题是我之前的问题.
推荐答案
我们可以把功能改成
f2 <- function(x) {
x1 <- max(x)
repeat {
i1 <- grepl(sub(" \\+ ", "|", names(which.max(x))), names(x))
if(all(i1)) break
x <- x[!i1]
x1 <- c(x1, max(x))
}
return(list(x, mean(x1)))
}
f2(res)
#[[1]]
#a1 + b1 a1 + b2 a1 + b3 a1 + b4 a1 + b5 a1 + b6
# 2 3 4 5 6 7
#[[2]]
#[1] 16
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