Swift 块值错误 [英] Swift Block value error

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本文介绍了Swift 块值错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我一直在快速收到完成块错误.错误是:

I keep getting a finish block error in swift. The error is:

不能调用非函数类型的值'((Array,Array)->())!

Cannot call value of non-function type'((Array,Array)->())!

下面还有一张错误图片.代码如下:

There's an image of the error below as well. Here's the code:

var blockFinih: ((_ selectedTags: Array<Tag>, _ unSelectedTags: Array<Tag>) -> ())!

func finishTagController() {
    var selected: Array<Tag> = Array()
    var unSelected: Array<Tag> = Array()

    for currentTag in tags {
        if currentTag.isSelected {
            selected.append(currentTag)
        }
        else {
            unSelected.append(currentTag)
        }
    }
    self.dismiss(animated: true, completion: { () -> Void in
        self.blockFinih(selectedTags: selected, unSelectedTags: unSelected)
    })
}

推荐答案

调用 blockFinih 时不要指定参数标签.您已将其定义为没有参数标签.参数 selectedTagsunSelectedTags 只能在函数内部使用,不能被调用者使用.

Don't specify the argument labels when you call blockFinih. You've defined it to have no argument labels. The parameters selectedTags and unSelectedTags can only be used inside the function, not by the caller.

变化:

self.blockFinih(selectedTags: selected, unSelectedTags: unSelected)

到:

self.blockFinih(selected, unSelected)

这篇关于Swift 块值错误的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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