“NSURL"不能隐式转换为“URL"；您的意思是使用“as"来显式转换吗?在迅速 3 [英] “NSURL” is not implicitly convertible to “URL”; did you mean to use “as” to explicitly convert? in swift 3

问题描述

func application(application: UIApplication, openURL url: NSURL, sourceApplication: String?, annotation: AnyObject) -> Bool
{
    return FBSDKApplicationDelegate.sharedInstance().application(application, openURL: url, sourceApplication: sourceApplication, annotation: annotation)
}

推荐答案

在 swift 3.0 中，openURL 的方法签名是:

In swift 3.0, the method signature for openURL is:

func application(_ application: UIApplication, open url: URL, sourceApplication: String?, annotation: Any) -> Bool {

            return FBSDKApplicationDelegate.sharedInstance().application(applic‌​ation, open: url, sourceApplication: sourceApplication, annotation: annotation)
    }

方法签名中，NSURL改为URL.

这篇关于“NSURL"不能隐式转换为“URL"；您的意思是使用“as"来显式转换吗?在迅速 3的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！