SwiftUI:将绑定转换为另一个绑定 [英] SwiftUI: transform Binding into another Binding

问题描述

有没有办法例如逻辑否定 Binding?例如，我有一个状态变量

Is there a way to e.g. logically negate Binding<Bool>? For example, I've a state variable

@State var isDone = true

我将其作为投标传递到不同的子视图中.然后我想使用它，例如在 NavigationLink 中使用 isActive，这样它只在 not isDone 时显示:

which I pass as a biding into different sub views. Then I want to use it e.g. with isActive in NavigationLink, so that it shows only when not isDone:

NavigationLink(destination: ..., isActive: ! self.$isDone ) // <- `!` means `not done`

当然，我可以用 isDone -> 来反转我的逻辑.isNotDone，但在许多情况下它是不自然的.那么有没有简单的方法来反转 bool 绑定?

Of course, I can invert my logic with isDone -> isNotDone, but it would be unnatural in many contexts. So is there any simple way to make inverse of a bool binding?

推荐答案

如果我理解正确，您需要以下内容:

If I correctly understood you need the following:

extension Binding where Value == Bool {
    public func negate() -> Binding<Bool> {
        return Binding<Bool>(get:{ !self.wrappedValue }, 
            set: { self.wrappedValue = !$0})
    }
}

struct TestInvertBinding: View {
    @State var isDone = true
    var body: some View {
        NavigationView {
            NavigationLink(destination: Text("Details"), 
                isActive: self.$isDone.negate()) {
                Text("Navigate")
            }
        }
    }
}

struct TestInvertBinding_Previews: PreviewProvider {
    static var previews: some View {
        TestInvertBinding()
    }
}

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