将一个 C 结构转换为另一个 [英] Casting one C structure into another

问题描述

我有两个相同(但名称不同)的 C 结构:

I have two identical (but differently named) C structures:

typedef struct {
      double x;
      double y;
      double z;
} CMAcceleration;


typedef struct {
    double x;
    double y;
    double z;   
} Vector3d;

现在我想将 CMAcceleration 变量分配给 Vector3d 变量(复制整个结构).我该怎么做?

Now I want to assign a CMAcceleration variable to a Vector3d variable (copying the whole struct). How can I do this?

我尝试了以下操作，但收到这些编译器错误:

I tried the following but get these compiler errors:

vector = acceleration;           // "incompatible type"
vector = (Vector3d)acceleration; // "conversion to non-scalar type requested"

当然我可以单独设置所有成员:

Of course I can resort to set all members individually:

vector.x = acceleration.x;
vector.y = acceleration.y;
vector.z = acceleration.z;

但这似乎很不方便.

最好的解决方案是什么?

What's the best solution?

推荐答案

那是你唯一的解决方案(除了将它包装成一个函数):

That's your only solution (apart from wrapping it into a function):

vector.x = acceleration.x;
vector.y = acceleration.y;
vector.z = acceleration.z;

你实际上可以像这样(使用指针)转换它

You could actually cast it, like this (using pointers)

Vector3d *vector = (Vector3d*) &acceleration;

但这不在规范中，因此行为取决于编译器、运行时和大型绿色空间怪物.

but this is not in the specs and therefore the behaviour depends on the compiler, runtime and the big green space monster.

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