如何从另一个数组值滤波器阵列值，并返回新的数组？ [英] How to filter array values from another arrays values and return new array?

问题描述

我有两个数组： $ all_languages​​ 和 $ taken_languages​​ 。一个包含了所有语言（如200或东西），但第二个 - 这已经被选择之前（从0到200）语言

I have two arrays: $all_languages and $taken_languages. One contains all languages (like 200 or something), but second - languages that have been chosen before (from 0 to 200).

我要删除已拍摄（ $ taken_languages​​ ）从 $ all_languages​​ 所有的语言，并返回新数组 - $ available_languages​​

I need to remove all languages that have been taken ($taken_languages) from $all_languages and return new array - $available_languages.

我的解决办法是两个回路，但是，首先，预期它不工作，第二个 - 这是'不酷'，我认为有更好的解决方案！你可以点我到正确的道路？

My solution was two loops, but, first, it doesn't work as expected, second - it's 'not cool' and I believe that there are better solutions! Can you point me to the correct path?

这是我以前做过，但是，正如我所说，这是行不通的预期...

This is what I have done before, but, as I said, it doesn't work as expected...

if (!empty($taken_languages)) {

    foreach ($all_languages as $language) {

        foreach ($taken_languages as $taken_language) {

            if ($taken_language != $language) {

                $available_languages[] = $language;

                break;

            }

        }

    }

} else {

    $available_languages = $all_languages;

}

谢谢指教！

推荐答案

PHP有一个内置该功能（和只是一切：P）

PHP has a built in function for this (and just about everything else :P)

$available_languages = array_diff($all_languages, $taken_languages);

PHP手册（和array_diff）

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