C++中的切换案例 [英] Switch Case in c++

问题描述

如何使用 switch-case 比较 C++ 中的字符数组?这是我的代码的一部分:

How can I compare an array of char in c++ using switch-case? Here is a part of my code:

char[256] buff;
switch(buff){
case "Name": printf("%s",buff);
             break;
case "Number": printf("Number "%s",buff);
               break;
defaul : break
}

我收到错误:错误:开关数量不是整数".我该如何解决?

I receive the error :" error: switch quantity not an integer".How can I resolve it?

推荐答案

如果您确实需要 switch 语句，则需要将 buff 变量转换为整数.为此，您可以使用哈希函数或 std::map.

If you really need a switch statement, you will need to convert your buff variable to an integer. To do so, you could use a hash function or a std::map.

简单的方法是制作一个 std::map<std::string,int> ，其中包含您要在与唯一 int 价值观.你会得到类似的东西:

The easy approach would be to make a std::map<std::string,int> containing the keys you want to use in the switch associated with unique int values. You would get something like:

std::map<string,int> switchmap;
...
switch(switchmap.find(std::string(buff))->second){
...
}

std::map 方法非常易读，不会引起太多混淆.

The std::map approach is very readable and shouldn't cause much confusion.

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