php中如何正确使用switch函数 [英] how to properly use switch function in php

问题描述

我想对单选按钮的值使用开关功能，但我不知道如何正确使用它.

i want to use switch function on value of radio button but i don't know how to proper use it.

 if(isset($_POST['Itemtype']))
    {
    $Itemtype = $_POST["Itemtype"];                             
switch ($Itemtype)
    {
    case "Ingredient":
    $Brandname = $_POST["Brandname"];

if(isset($_POST['Brandname']))
    {
    $try2 = "Brandname working";
    }
    else
    {
    $errormsg = 'error on branchname';
    }
    break;
    case "Miscellaneous":
    $Size = $_POST["Size"];
    $Color = $_POST["Color"];
    if(isset($_POST['Size']))
    {
    $try2 = "Misc working";
    }
    else
    {
    $errormsg = 'error on size';
    break;
    }
  else
{
$errormsg = 'error5';
}

我对字符串部分的错误:) 但它不检查品牌名称是否已设置或为空.

my bad on the string part :) but it doesn't check if brandname is set or null.

推荐答案

问题是你的字符串不在引号内，例如:case Miscellaneous: should be case "Miscellaneous":

problem is that your strings aren't inside quotes ex : case Miscellaneous: should be case "Miscellaneous":

这篇关于php中如何正确使用switch函数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！