在 EntityRepository 中访问当前登录的用户 [英] Access currently logged in user in EntityRepository

问题描述

我想创建一个简单的博客示例，其中用户将最喜欢的类别附加到该帐户.这意味着只能为此类别撰写文章.(其中一些 - 主要是管理员 - 将有机会切换类别，但这不是问题......现在^^)

I want to create a simple blog example where users have a favourite category attached to there account. This means the can only write articles for this category. (Some of them - mostly admins -will get the opportunity to switch categories, but that's not the problem... for now ^^)

所以我首先创建了 User- 和 Category 实体之间的关系.一切正常.每个用户现在都选择了一个主要类别.

So I first created a relation between the User- and the Category entity. Everything works fine. Each user now has a main category selected.

唯一困扰我的是我无法在 EntityType (formbuilder) 和 EntityRepository 类中获取当前登录的用户.

Only thing which bothers me, is that I cant get hold of the current logged in user in the EntityType (formbuilder) and EntityRepository classes.

在我的新帖子"表单中，存在与其他实体(例如标签)的关系.我使用 EntityType 类中的实体"表单类型来生成这些表单元素.现在我不想过滤标签，只允许选择与当前登录的用户类别具有相同类别关系的标签.

In my "New Post" form there are relations to other entities (e.g. Tags). I use the 'entity' formtype in the EntityType class to generate these form elements. Now i wan't to filter the tags, to only allow tags which have the same category relation as the currently logged in users category to be selectable.

我尝试使用实体表单类型中的 query_builder 选项.但是由于我无法获取当前用户对象，我不知道他选择了哪个类别.EntityRepository 也有同样的问题.

I tried to use the query_builder option from the entity formtype. But as i can't get the current user object, I don't know which category he has selected. Same problem with the EntityRepository.

现在我可以过滤 PostController 中已有的标签，但问题是，我会一遍又一遍地需要它.因此，我不想每次添加新内容时都对此进行编码.

Now I could filter the tags already in the PostController but the problem is, that I will need this over and over again. And therefore I don't wan't to code this everytime I add something new.

我认为最好将此过滤器放在 EntityRepository 中.所以我总是可以访问 findAllByCategory.但我需要那里的用户对象.

I thought it would be the best to place this filter in the EntityRepository. So I can always access the findAllByCategory. But I need the user-object in there.

实现这一目标的最佳方法是什么?已经搜索了很多，但要么我搜索了错误的术语，要么没有人遇到这个问题:)

What is the best way to accomplish this? Have searched a lot, but either I searched for the wrong terms or no one has this problem :)

推荐答案

您可以在定义为服务的表单类型中注入安全上下文.然后在您的标签字段中使用带有 $user(当前登录的用户)的查询构建器来过滤与当前登录的具有相同类别关系的标签:

You can inject security context in your form type defined as a service. Then in your tags field use the query builder with $user (current logged user) to filter tags which have the same category relation as the currently logged:

/** @DI\Service("form.type.post") */
class PostType extends \Symfony\Component\Form\AbstractType
{
    /**
     * @var \Symfony\Component\Security\Core\SecurityContext
     */
    protected $securityContext;

    /**
     * @DI\InjectParams({"securityContext" = @DI\Inject("security.context")})
     *
     * @param \Symfony\Component\Security\Core\SecurityContext $context
     */
    public function __construct(SecurityContext $securityContext)
    {
        $this->securityContext = $securityContext;
    }

    public function buildForm(FormBuilder $builder, array $options)
    {
        $user = $this->securityContext()->getToken()->getUser();

        $builder->add('tags', 'entity', array(
            'label'         => 'Tags',
            'class'         => 'Acme\HelloBundle\Entity\Tag',
            'property'      => 'name',
            'query_builder' => function(EntityRepository $er) use($user) {
                return $er->getAllSuitableForUserChoiceQueryBuilder($user);
            },
            'multiple'      => true,
            'expanded'      => true,
    }
}

将标签过滤到您的存储库中:

Filter tags into your repository:

class TagRepository extends EntityRepository
{
    public function getAllSuitableForUserChoiceQueryBuilder(User $user)
    {
        // Filter tags that can be selected by a given user
    }
}

这篇关于在 EntityRepository 中访问当前登录的用户的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！