如何初始化在C多维字符数组？ [英] How to Initialize a Multidimensional Char Array in C?

问题描述

我想从C＃转换某些code到C，以便它可以被刻录到微控制器。

可能有人请告诉我，我怎么会在C＃中的二维字符串数组转换成的东西用C？

我的C＃code是这样的：

 字符串[，] DirectionPosition = {{00，10，，01，}，
                                        {01，11，，02，00}，
                                        {02，12，，03，01}，
                                        {03，13，，04，02}，
                                        {04，14，，，03}，
                                        {10，20，00，11，}，
                                        {11，21，01，12，10}，
                                        {12，22，02，13，11}，
                                        。
                                        。
                                        。
                                        。
                                        {44，，34，，43}，};
 

而且，我将如何访问元素？
在C＃中，如果我在第三排想要的第二个元素，将仅仅是DirectionPosition [2,1]，但究竟是什么，等效时，有C中没有字符串要少得多的2-D字符串数组？

解决方案

 字符DirectionPosition [] [5] [3] = {{00，10，， 01，}，
                                    {01，11，，02，00}，
                                    {02，12，，03，01}，
                                    {03，13，，04，02}，
                                    {04，14，，，03}，
                                    {10，20，00，11，}，
                                    {11，21，01，12，10}，
                                    {12，22，02，13，11}，
                                    。
                                    。
                                    。
                                    。
                                    {44，，34，，43}，};
 

C有没有内置的字符串类，你必须凑合用字符数组。你可以选择使用指针指向char。

I'm trying to convert some code from C# to C so that it can be burnt onto a microcontroller.

Could someone please tell me how I would convert a two dimensional string array in C# into something in C?

My C# code looks like this:

string[,] DirectionPosition = {{"00", "10", "", "01", ""},
                                        {"01", "11", "", "02", "00"},
                                        {"02", "12", "", "03", "01"},
                                        {"03", "13", "", "04", "02"},
                                        {"04", "14", "", "", "03"},
                                        {"10", "20", "00", "11", ""},
                                        {"11", "21", "01", "12", "10"},
                                        {"12", "22", "02", "13", "11"},
                                        .
                                        .
                                        .
                                        .
                                        {"44", "", "34", "", "43"},};

And moreover, how would I access the elements? In C# if I wanted the second element in the third row it would simply be DirectionPosition[2,1] but what is the equivalent of that when there is no string in C much less 2-D string arrays?

解决方案

char DirectionPosition[][ 5 ][ 3 ] = {{"00", "10", "", "01", ""},
                                    {"01", "11", "", "02", "00"},
                                    {"02", "12", "", "03", "01"},
                                    {"03", "13", "", "04", "02"},
                                    {"04", "14", "", "", "03"},
                                    {"10", "20", "00", "11", ""},
                                    {"11", "21", "01", "12", "10"},
                                    {"12", "22", "02", "13", "11"},
                                    .
                                    .
                                    .
                                    .
                                    {"44", "", "34", "", "43"},};

C has no inbuilt string class, you have to make do with character arrays. You could alternatively use pointers to pointer to char.

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