c char字符数组初始化 [英] C char array initialization
问题描述
我不知道会在以下几个方面初始化之后的char数组中的内容。
I'm not sure what will be in the char array after initialization in the following ways.
1 字符BUF [10] =; 结果
2. 字符BUF [10] =; 结果
3. 字符BUF [10] =A;
有关情况2，我觉得 BUF [0] 应， BUF [1] 应'\\ 0'，并从 BUF [2] 到 BUF [9] 将是随机的内容。对于情况3，我觉得 BUF [0] 应'A'， BUF [ 1] 应该是'\\ 0'，从 BUF [2] 到 BUF [9] 将是随机的内容。
For case 2, I think buf[0] should be ' ', buf[1] should be '\0', and from buf[2] to buf[9] will be random content. For case 3, I think buf[0] should be 'a', buf[1] should be '\0', and from buf[2] to buf[9] will be random content.
这是否正确？
和为1的情况下，会在 BUF 是什么？ BUF [0] =='\\ 0'和 BUF [1] 到 BUF [9] 将是随机的内容？
And for the case 1, what will be in the buf? buf[0] == '\0' and from buf[1] to buf[9] will be random content?
推荐答案
这是不是你如何初始化数组，但对于：
This is not how you initialize an array, but for:
-
第一个声明：
The first declaration:
char buf[10] = "";
等同于
char buf[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
第二个声明：
The second declaration:
char buf[10] = " ";
等同于
char buf[10] = {' ', 0, 0, 0, 0, 0, 0, 0, 0, 0};
第三个声明：
The third declaration:
char buf[10] = "a";
等同于
char buf[10] = {'a', 0, 0, 0, 0, 0, 0, 0, 0, 0};
如你所见，没有随机的内容：如果有较少的初始化，数组的剩余与 0 初始化。这即使阵列函数内声明的情况。
As you can see, no random content: if there are fewer initializers, the remaining of the array is initialized with 0. This the case even if the array is declared inside a function.
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