char数组的初始化字符串太长 [英] Initializer-string for char array is too long

问题描述

我读过 char four [4] ="four";此语句的正确语义是什么?

我正在使用 Xcode 并编写 Objective C 代码.我不明白为什么:

I am using Xcode and writing Objective C code. I don't understand why:

char words[4] = { "aardvark", "abacus", "allude", "zygote" };

发出警告

警告:语义问题:char数组的初始化字符串太长

warning: Semantic Issue: Initializer-string for char array is too long

但是

char *words[4] = { "aardvark", "abacus", "allude", "zygote" };

正常工作.请引导我.

推荐答案

我不知道整数指针和字符指针之间的区别.因此，我感到困惑.这对我有帮助: http://www.computing.net/answers/programming/why-this-works-char-pointer-in-c/4444.html

I was not aware of the differences between an integer pointer and a character pointer. Hence, I was confused. This helped me: http://www.computing.net/answers/programming/why-this-works-char-pointer-in-c/4444.html

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