初始化字符串 [英] String initialization

问题描述

是什么

之间的区别

 字符海峡[32] ='\\ 0';
 

和

 字符海峡[32] =;
 

解决方案

既然你已经声明的大小，两个声明是完全平等的。但是，如果不指定大小，你可以看到，第一个声明中作出较大的字符串：

 的char a [] =一个\\ 0;
炭B〔] =一个;的printf（％I％I \\ N的sizeof（A）的sizeof（B））;
 

打印

  3 2
 

这是因为有两个空值（显式之一和隐式的），而仅b与隐一端。一个端

What is the difference between

char Str[32] = "\0";

and

char Str[32] = "";

解决方案

Since you already declared the sizes, the two declarations are exactly equal. However, if you do not specify the sizes, you can see that the first declaration makes a larger string:

char a[] = "a\0";
char b[] = "a";

printf("%i %i\n", sizeof(a), sizeof(b));

prints

3 2

This is because a ends with two nulls (the explicit one and the implicit one) while b ends only with the implicit one.

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