使所有符号在 sympy 表达式中可交换 [英] Make all symbols commutative in a sympy expression
问题描述
假设你在一个 sympy 表达式中有许多非交换符号,比如
a, c = sympy.symbols('a c', 可交换=假)b = sympy.Symbol('b')expr = a * c + b * c
使表达式中的所有符号都可交换的首选方法是什么,例如,sympy.simplify(allcommutative(expr)) = c * (a + b)
?>
在 this answer 中指出,如果不替换符号,但也许有一种简单的方法可以像这样在块中更改表达式的所有符号?
如果你想让 Eq(expr, c * (a + b))
计算为 True,你需要替换通勤的其他符号的符号.例如:
replacements = {s: sympy.Dummy(s.name) for s in expr.free_symbols}sympy.Eq(expr, c * (a + b)).xreplace(replacements).simplify()
这将返回 True.
Say you have a number of non commutative symbols within a sympy expression, something like
a, c = sympy.symbols('a c', commutative=False)
b = sympy.Symbol('b')
expr = a * c + b * c
What is the preferred way to make all symbols in the expression commutative, so that, for example, sympy.simplify(allcommutative(expr)) = c * (a + b)
?
In this answer it is stated that there is no way to change the commutativity of a symbol after creation without replacing a symbol, but maybe there is an easy way to change in blocks all symbols of an expression like this?
If you want Eq(expr, c * (a + b))
to evaluate to True, you'll need to replace symbols by other symbols that commute. For example:
replacements = {s: sympy.Dummy(s.name) for s in expr.free_symbols}
sympy.Eq(expr, c * (a + b)).xreplace(replacements).simplify()
This returns True.
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