Python3 上的无效语法错误 关于打印 [英] Invalid Syntax Error On Python3 About print

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本文介绍了Python3 上的无效语法错误 关于打印的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

def Corner(n):
  if n == 3:
    print('İts An Triangle \nBu Bir Üçgen')
  elif n == 4:
    print('İts An Rectangle or Square or Parrallelogram \nBu Bir 
   Dikdörtgen yada Kare yada ParalelKenar ')
  elif n == 5:
    print('İts An Pentagon \nBu Bir Beşgen')
  elif n == 6:
    print('İts An Hexagon \nBu Bir Altıgen')
  else:
    print('Bir Köşe Sayısı Girmediniz \nYou Didnt Wrote a Corner 
 Number '

print Corner(6)

**File "Köşegen.py", line 13
print Corner(6)
    ^
SyntaxError: invalid syntax**

这是我在 Python3 上写的错误代码这段关于角和形状的代码,但是当我运行代码时我得到了按摩

Its The Error Code I wrote it on Python3 This Code About the Corners and Shapes but I had that massage when I run the code

推荐答案

您缺少一些括号:

print('Bir Köşe Sayısı Girmediniz \nYou Didnt Wrote a Corner Number ') # here

print(Corner(6)) # and here

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