C++ 语法:void CLASS functionName()? [英] C++ syntax: void CLASS functionName()?

问题描述

我遇到了一些没有标题的独立代码.我相信它是直接的 C/C++，但我不确定.如果是这样，下面的CLASS"是什么意思?我知道这不是类声明或定义.这是一个名为CLASS"的类的方法吗?

I came across some standalone code without headers. I believe it to be straight C/C++, but am not sure. If so, what does the "CLASS" in the following mean? I know it's not a class declaration or definition. Is this a method of a class named "CLASS"?

void CLASS functionName(){
  //
  //
  //
}

我看惯了() {...}，但不是上面的.我是不是忘记了什么?(原谅我，因为我最近一直在研究 JS 和 Objective-C.)

I'm used to seeing <returnType> <functionName>() {...}, but not the above. Am I forgetting something? (Pardon me, as I've been in JS and Objective-C lately.)

推荐答案

虽然 AFAIK 不常见，但可能是 CLASS 是一个宏，如下所示.因为它的名字是 CLASS，我会说它更有可能是一个类或命名空间的宏.

Although it's not common AFAIK, it could be that CLASS is a macro as below. Since its name is CLASS, I would say it's more likely that it's a macro for a class or namespace.

1.班级名称

class A
{
   void functionName();
};

#define CLASS A::

void CLASS functionName()
{}

2.命名空间

namespace A
{
   void functionName();
};

#define CLASS A::

void CLASS functionName()
{}

3.调用转换

// or __cdecl, etc.
define CLASS __stdcall

4.其他

可能还有其他语法正确的(例如，指针的宏)，但在您的情况下不太可能.或者它可能只是一个评论，正如 Hostile 在下面指出的那样.

There could be others (e.g., a macro for a pointer) which are syntactically correct, but they're less likely in your case. Or it could simply be a comment, as Hostile points out below.

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